30th June 2010
Session 2.3
Population Inference
Confidence Intervals – Proportion
Confidence Intervals – Proportion
Population Level
E = Event
= Definition of Event of Interest
P = Pr{E} = True Probability for Event E
Sample Level
e = Number
of Observed Events in Sample
n = Number
of Observations / Sample Size Number of Trials
p = e/n =
Proportion of Total Sample Observing Event E
sdp = sqrt(p*(1 – p)/n) = Sample Standard
Error for the Proportion
Z =
Confidence Coefficient
Confidence
Interval is given as [ (p – Z*sdp), (p + Z*sdp) ]
Validation of the Confidence
Interval Process – Population Proportion (Current: from Summer 2010)
Track the event “Face Value Shows 3
or 4” in n=50 tosses of a fair, six-sided dice (face values 1,2,3,4,5,6 per face).
We know that P=Pr{Face
Value Shows as 3 or 4} = Pr{Face Value Shows as 3} + Pr{Face Value Shows as 4}
= (1/6) + (1/6) = 2/6 = 1/3 ≈
0.3333, so we can check our intervals for accuracy. In 20 intervals, we have zero failures and 20
successes, yielding a failure rate of 0% (versus 5% , as expected).
Samples
0 Miss in 20 Intervals
(0%), 20 Hits in 20 Intervals (100%)
Sample |
3 or 4 Shows |
p3or4 |
sdp = sqrt(p*(1-p)/50) |
Lower95 = p - 2*sdp |
Upper95 = p - 2*sdp |
P3or4 |
Status |
Perfect |
16.6667 |
0.333333 |
0.066667 |
0.2 |
0.466667 |
0.333333 |
Perfect |
#1 |
17 |
17/50 = 0.34 |
sqrt((17/50)*(33/50)/50)
≈ .066993 |
(17/50) -
2*sqrt((17/50)*(33/50)/50) ≈0.206015 |
0.473985 |
0.333333 |
Hit – CI contains
0.3333 |
#2 |
13 |
0.26 |
0.062032 |
0.135936 |
0.384064 |
0.333333 |
Hit – CI contains
0.3333 |
#3 |
14 |
0.28 |
0.063498 |
0.153004 |
0.406996 |
0.333333 |
Hit – CI contains
0.3333 |
#4 |
15 |
0.3 |
0.064807 |
0.170385 |
0.429615 |
0.333333 |
Hit – CI contains
0.3333 |
#5 |
17 |
0.34 |
0.066993 |
0.206015 |
0.473985 |
0.333333 |
Hit – CI contains
0.3333 |
#6 |
15 |
0.3 |
0.064807 |
0.170385 |
0.429615 |
0.333333 |
Hit – CI contains
0.3333 |
#7 |
14 |
0.28 |
0.063498 |
0.153004 |
0.406996 |
0.333333 |
Hit – CI contains
0.3333 |
#8 |
17 |
0.34 |
0.066993 |
0.206015 |
0.473985 |
0.333333 |
Hit – CI contains
0.3333 |
#9 |
13 |
0.26 |
0.062032 |
0.135936 |
0.384064 |
0.333333 |
Hit – CI contains
0.3333 |
#10 |
17 |
0.34 |
0.066993 |
0.206015 |
0.473985 |
0.333333 |
Hit – CI contains
0.3333 |
#11 |
18 |
0.36 |
0.067882 |
0.224235 |
0.495765 |
0.333333 |
Hit – CI contains
0.3333 |
#12 |
13 |
0.26 |
0.062032 |
0.135936 |
0.384064 |
0.333333 |
Hit – CI contains
0.3333 |
#13 |
19 |
0.38 |
0.068644 |
0.242712 |
0.517288 |
0.333333 |
Hit – CI contains
0.3333 |
#14 |
21 |
0.42 |
0.0698 |
0.280401 |
0.559599 |
0.333333 |
Hit – CI contains
0.3333 |
#15 |
20 |
0.4 |
0.069282 |
0.261436 |
0.538564 |
0.333333 |
Hit – CI contains
0.3333 |
#16 |
14 |
0.28 |
0.063498 |
0.153004 |
0.406996 |
0.333333 |
Hit – CI contains
0.3333 |
#17 |
13 |
0.26 |
0.062032 |
0.135936 |
0.384064 |
0.333333 |
Hit – CI contains
0.3333 |
#18 |
16 |
0.32 |
0.06597 |
0.188061 |
0.451939 |
0.333333 |
Hit – CI contains
0.3333 |
#19 |
11 |
0.22 |
0.058583 |
0.102833 |
0.337167 |
0.333333 |
Hit – CI contains
0.3333 |
#20 |
12 |
0.24 |
0.060399 |
0.119203 |
0.360797 |
0.333333 |
Hit – CI contains
0.3333 |
Validation of the Confidence
Interval Process – Population Proportion (from Spring 2009)
Track the event “Sum = 7” in n=50
tosses of a fair of fair, six-sided dice (face values 1,2,3,4,5,6 per face).
We know that P=Pr{Sum =
7} = 6/36 = 1/6 ≈
0.1667, so we can check our intervals for accuracy. In 26 intervals,
we have one failure and 25 successes,
yielding a failure rate of approximately 3.8% (versus expected 5%).
Event Count for (Sum=7) |
p=e/50 |
sdp = sqrt(p*(1-p)/50) |
lower95 = p-*2sdp |
upper95 = p+2*sdp |
P=Pr{Sum=7} |
Result (Contains
P=1/6?) |
11 |
0.22 |
0.0585833 |
0.102833452 |
0.337166548 |
(1/6) » 0.1667 |
Hit |
10 |
0.2 |
0.0565685 |
0.086862915 |
0.313137085 |
(1/6) » 0.1667 |
Hit |
9 |
0.18 |
0.0543323 |
0.071335378 |
0.288664622 |
(1/6) » 0.1667 |
Hit |
8 |
0.16 |
0.0518459 |
0.056308149 |
0.263691851 |
(1/6) » 0.1667 |
Hit |
4 |
0.08 |
0.0383667 |
0.003266696 |
0.156733304 |
(1/6) » 0.1667 |
Miss |
13 |
0.26 |
0.0620322 |
0.135935501 |
0.384064499 |
(1/6) » 0.1667 |
Hit |
9 |
0.18 |
0.0543323 |
0.071335378 |
0.288664622 |
(1/6) » 0.1667 |
Hit |
7 |
0.14 |
0.0490714 |
0.041857247 |
0.238142753 |
(1/6) » 0.1667 |
Hit |
7 |
0.14 |
0.0490714 |
0.041857247 |
0.238142753 |
(1/6) » 0.1667 |
Hit |
6 |
0.12 |
0.0459565 |
0.028086998 |
0.211913002 |
(1/6) » 0.1667 |
Hit |
9 |
0.18 |
0.0543323 |
0.071335378 |
0.288664622 |
(1/6) » 0.1667 |
Hit |
12 |
0.24 |
0.0603987 |
0.119202649 |
0.360797351 |
(1/6) » 0.1667 |
Hit |
7 |
0.14 |
0.0490714 |
0.041857247 |
0.238142753 |
(1/6) » 0.1667 |
Hit |
9 |
0.18 |
0.0543323 |
0.071335378 |
0.288664622 |
(1/6) » 0.1667 |
Hit |
5 |
0.1 |
0.0424264 |
0.015147186 |
0.184852814 |
(1/6) » 0.1667 |
Hit |
7 |
0.14 |
0.0490714 |
0.041857247 |
0.238142753 |
(1/6) » 0.1667 |
Hit |
12 |
0.24 |
0.0603987 |
0.119202649 |
0.360797351 |
(1/6) » 0.1667 |
Hit |
10 |
0.2 |
0.0565685 |
0.086862915 |
0.313137085 |
(1/6) » 0.1667 |
Hit |
10 |
0.2 |
0.0565685 |
0.086862915 |
0.313137085 |
(1/6) » 0.1667 |
Hit |
8 |
0.16 |
0.0518459 |
0.056308149 |
0.263691851 |
(1/6) » 0.1667 |
Hit |
12 |
0.24 |
0.0603987 |
0.119202649 |
0.360797351 |
(1/6) » 0.1667 |
Hit |
13 |
0.26 |
0.0620322 |
0.135935501 |
0.384064499 |
(1/6) » 0.1667 |
Hit |
5 |
0.1 |
0.0424264 |
0.015147186 |
0.184852814 |
(1/6) » 0.1667 |
Hit |
7 |
0.14 |
0.0490714 |
0.041857247 |
0.238142753 |
(1/6) » 0.1667 |
Hit |
10 |
0.2 |
0.0565685 |
0.086862915 |
0.313137085 |
(1/6) » 0.1667 |
Hit |
10 |
0.2 |
0.0565685 |
0.086862915 |
0.313137085 |
(1/6) » 0.1667 |
Hit |
From http://www.mindspring.com/~cjalverson/2ndhourlySummer2008Key.htm
Second Hourly, Summer 2008, Version A
The top number
is the systolic blood pressure reading.
It represents the maximum pressure exerted when the heart contracts. The bottom number is the diastolic blood pressure
reading. It represents the pressure in the arteries when the heart is at rest. A sample of FHS adult subjects yields the
following readings:
124/88, 140/90,
156/108, 130/70,
175/75, 136/84, 124/84, 144/88,
128/74, 154/90, 160/92, 210/120, 110/75, 166/108, 100/70, 172/110,
160/90, 145/75, 122/84, 162/80, 156/84, 120/65, 128/84, 130/90, 210/110,
110/68, 160/106, 140/90, 132/72, 120/80, 200/100, 165/105,
132/88, 134/84, 120/75, 138/85, 118/86, 152/74, 138/70, 124/74, 122/80, 155/90,
160/100, 294/144, 140/82, 132/86, 120/80, 200/130, 126/86,
150/100, 135/75, 140/78, 142/85, 146/94, 185/90, 166/78, 190/100,
160/80, 140/80, 120/80,150/95, 124/75, 150/110, 140/84, 130/82, 130/80, 230/124,
128/72, 220/118, 130/80, 165/95, 208/114, 126/80, 140/90, 166/104,
130/70, 130/80, 120/90
Case Two | Confidence
Interval: Population Proportion |
Using the data and context from Case One, compute and interpret a
95% confidence interval for the population proportion of Framingham Heart Study
subjects with Systolic Blood Pressure strictly greater than 160 mm Hg. work. Fully discuss the results. This discussion must
include a clear discussion of the population and the population proportion, the
family of samples, the family of intervals and the interpretation of the
interval.
Numbers
n
event
p sdp
z lower upper
78
18 0.23077 0.047706
2 0.13536 0.32618
event = number of FHS subjects in the sample with SBP
> 160 = 18
p = event/n = 18/78
≈ 0.23077
sdp = sqrt(p*(1-p)/n) = sqrt((18/78)*(60/78)/78) » 0.047706
Table 1. Means and Proportions
Z(k) PROBRT PROBCENT 0.05 0.48006 0.03988 0.10 0.46017 0.07966 0.15 0.44038 0.11924 0.20 0.42074 0.15852 0.25 0.40129 0.19741 0.30 0.38209 0.23582 0.35 0.36317 0.27366 0.40 0.34458 0.31084 0.45 0.32636 0.34729 0.50 0.30854 0.38292 0.55 0.29116 0.41768 0.60 0.27425 0.45149 0.65 0.25785 0.48431 0.70 0.24196 0.51607 0.75 0.22663 0.54675 0.80 0.21186 0.57629 0.85 0.19766 0.60467 0.90 0.18406 0.63188 0.95 0.17106 0.65789 1.00 0.15866 0.68269 |
Z(k) PROBRT PROBCENT 1.05 0.14686 0.70628 1.10 0.13567 0.72867 1.15 0.12507 0.74986 1.20 0.11507 0.76986 1.25 0.10565 0.78870 1.30 0.09680 0.80640 1.35 0.088508 0.82298 1.40 0.080757 0.83849 1.45 0.073529 0.85294 1.50 0.066807 0.86639 1.55 0.060571 0.87886 1.60 0.054799 0.89040 1.65 0.049471 0.90106 1.70 0.044565 0.91087 1.75 0.040059 0.91988 1.80 0.035930 0.92814 1.85 0.032157 0.93569 1.90 0.028717 0.94257 1.95 0.025588 0.94882 2.00 0.022750
0.95450 |
Z(k) PROBRT PROBCENT 2.05 0.020182 0.95964 2.10 0.017864 0.96427 2.15 0.015778 0.96844 2.20 0.013903 0.97219 2.25 0.012224 0.97555 2.30 0.010724 0.97855 2.35 0.009387 0.98123 2.40 0.008198 0.98360 2.45 0.007143 0.98571 2.50 0.006210 0.98758 2.55 0.005386 0.98923 2.60 0.004661 0.99068 2.65 0.004025 0.99195 2.70 .0034670 0.99307 2.75 .0029798 0.99404 2.80 .0025551 0.99489 2.85 .0021860 0.99563 2.90 .0018658 0.99627 2.95 .0015889 0.99682 3.00 .0013499 0.99730 |
from 2.00 0.022750 0.95450, Z ≈2.00
upper = p ─ z*sdp ≈ 0.23077 ─ 2*0.047706 ≈
0.13536
upper = p + z*sdp ≈ 0.23077 + 2*0.047706 ≈
0.32618
We estimate the
population proportion of Framingham Heart Study (FSH) subjects whose systolic
blood pressure (SBP) strictly exceeds 160 mm Hg.
Each member of our family
of samples is a single random sample of 78 Framingham Heart Study (FSH)
subjects, and the family of samples consists of all possible samples of this
type.
From each member of the
family of samples, we compute event( = number of FHS subjects in the sample with SBP > 160), p( =
event/n), sdp(= sqrt(p*(1-p)/n)) and the interval [p ─ z*sdp, p + z*sdp].
Approximately 95% of the
member samples yield intervals containing the true population proportion of FHS
subjects whose SBP strictly exceeds 160 mm Hg.
If our interval resides
within this super-majority, then between 13.5% and 32,6% of FHS subjects have SBP strictly exceeding 160
mm Hg.
From http://www.mindspring.com/~cjalverson/3rd%20Hourly%20Spring%202007%20Version%20A%20Key.htm
Third
Hourly, Spring 2007,
Version A
Case Three
Confidence Interval: Population
Proportion
Traumatic Brain Injury (TBI) and
Glasgow Coma Scale (GCS)
The Glasgow Coma Scale (GCS)
is the most widely used system for scoring the level of consciousness of a
patient who has had a traumatic brain injury. GCS is based on the patient's
best eye-opening, verbal, and motor responses. Each response is scored and then
the sum of the three scores is computed. That is,
Glasgow Coma Scale Categories: Mild
(13-15); Moderate (9-12) and Severe/Coma (3-8)
Traumatic brain injury (TBI) 1,
2 is an
insult to the brain from an external mechanical force, possibly leading to
permanent or temporary impairments of cognitive, physical, and psychosocial
functions with an associated diminished or altered state of consciousness.
Consider a random sample of patients with TBI, with GCS at initial treatment
and diagnosis listed below:
3, 3, 3, 4, 4, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 6, 6, 6,
6, 6, 6, 7, 7, 7, 7 8, 8, 8, 9, 9, 9,
9, 9, 9, 9, 9, 10, 10, 10, 10, 10, 11, 11, 11, 12, 12, 13, 13, 13,
14, 14, 14, 14, 14, 14, 15
Consider the
proportion of TBI patients presenting severe GCS. Compute and interpret a 97%
confidence interval for
this population proportion. Show your work. Fully discuss the results. This
discussion must include a clear discussion of the population and the population
proportion, the family of samples, the family of intervals and the
interpretation of the interval.
1: http://www2.state.tn.us/health/statistics/PdfFiles/TBI_Rpt_2000-2004.pdf
2: http://www.aemj.org/cgi/content/abstract/10/5/491
Numbers
3, 3, 3, 4, 4 | 4, 4, 4, 4, 5 | 5, 5, 5, 5, 5 | 5, 5, 5, 5, 6 | 6,
6, 6, 6, 6 | 7, 7, 7, 7 8 | 8, 8, 9, 9, 9 |
9, 9, 9, 9, 9 | 10, 10, 10, 10, 10 | 11, 11, 11, 12, 12 | 13, 13,
13, 14, 14 | 14, 14, 14, 14, 15
n = sample size = 60
Event = “TBI Patient
Initially Presents with GCS Severe (3 ≤ GCS ≤ 8).”
e = sample event
count
= 32
p = e/n = 32/60
≈ .5333
sdp = sqrt(p*(1–p)/n) = sqrt((32/60)*(28/60)/60)
≈ 0.064406
Table 1. Means and Proportions
Z(k) PROBRT 0.05 0.48006 0.03988 0.10 0.46017 0.07966 0.15 0.44038 0.11924 0.20 0.42074 0.15852 0.25 0.40129 0.19741 0.30 0.38209 0.23582 0.35 0.36317 0.27366 0.40 0.34458 0.31084 0.45 0.32636 0.34729 0.50 0.30854 0.38292 0.55 0.29116 0.41768 0.60 0.27425 0.45149 0.65 0.25785 0.48431 0.70 0.24196 0.51607 0.75 0.22663 0.54675 0.80 0.21186 0.57629 0.85 0.19766 0.60467 0.90 0.18406 0.63188 0.95 0.17106 0.65789 1.00 0.15866 0.68269 |
Z(k) PROBRT P 1.05 0.14686 0.70628 1.10 0.13567 0.72867 1.15 0.12507 0.74986 1.20 0.11507 0.76986 1.25 0.10565 0.78870 1.30 0.09680 0.80640 1.35 0.088508 0.82298 1.40 0.080757 0.83849 1.45 0.073529 0.85294 1.50 0.066807 0.86639 1.55 0.060571 0.87886 1.60 0.054799 0.89040 1.65 0.049471 0.90106 1.70 0.044565 0.91087 1.75 0.040059 0.91988 1.80 0.035930 0.92814 1.85 0.032157 0.93569 1.90 0.028717 0.94257 1.95 0.025588 0.94882 2.00 0.022750 0.95450 |
Z(k) PROBRT PR 2.05 0.020182 0.95964 2.10 0.017864 0.96427 2.15 0.015778 0.96844 2.20 0.013903
0.97219 2.25 0.012224 0.97555 2.30 0.010724 0.97855 2.35 0.009387 0.98123 2.40 0.008198 0.98360 2.45 0.007143 0.98571 2.50 0.006210 0.98758 2.55 0.005386 0.98923 2.60 0.004661 0.99068 2.65 0.004025 0.99195 2.70 .0034670 0.99307 2.75 .0029798 0.99404 2.80 .0025551 0.99489 2.85 .0021860 0.99563 2.90 .0018658 0.99627 2.95 .0015889 0.99682 3.00 .0013499 0.99730 |
Z = 2.20 from the row 2.20
0.013903 0.97219.
Lower Bound = p – 2.2*sdp ≈ .5333 –
2.2*0.064406 ≈ 0.39164
Upper Bound = p + 2.2*sdp ≈ .5333 +
2.2*0.064406 ≈ 0.67503
Discussion
Our population is
the population of people with Traumatic Brain Injury (TBI).
Our Family of Samples
(FoS) consists of every possible random sample of 60
people with TBI.
From each member sample
of the FoS, we compute the interval [Lower Bound, Upper
Bound] =
[p – 2.2*sdp, p + 2.2*sdp], where
sdp = sqrt(p*(1–p)/n). Computing this interval
for each member sample of the FoS, we obtain a Family of Intervals (FoI), approximately 97% of
which cover the true population proportion of TBI cases with initially severe
TBI.
If our interval, [.3916,
.6750] is among the approximate 97% super-majority of intervals that cover the
population proportion, then between 39.2% and 67.5% of TBI cases initially
present with severe (3 ≤ GCS ≤ 8) TBI.
From http://www.mindspring.com/~cjalverson/CompFinalSpring2008verWednesdayKey.htm
Final Examination, Spring 2008, Version Wednesday
Case Three | Confidence
Interval for Proportion | Gestational Age
Consider the proportion
of Year 2005 US Resident Live Births that are “Full Term,” that is births with [37,40] weeks of gestation at birth. Using the
data from Case Two, compute and interpret a 98% confidence interval for this
population proportion.
Gestational age is the time spent between conception and birth,
usually measured in weeks. In general, infants born after 36 or fewer weeks of
gestation are defined as premature, and may face significant challenges in
health and development. Infants born after
37-40 weeks of gestation are generally viewed as full term, and those born after 41 or more weeks of
gestation are generally viewed as post term. Suppose that a random sample of
2005 US resident live born infants yields the following gestational ages (in
weeks):
25, 26, 27, 29, 30, 32, 33, 34, 34, 35, 35, 36, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37,
38, 38, 38, 38, 38 38,38, 38, 38, 38, 38, 38, 39, 39, 39, 40, 40, 40, 40, 40,
40, 40, 40, 40, 40, 41, 41, 41, 42, 42,
42, 43, 43
Numbers
Table 1.
Means and Proportions
Z(k) PROBRT PROBCENT 0.05 0.48006 0.03988 0.10 0.46017 0.07966 0.15 0.44038 0.11924 0.20 0.42074 0.15852 0.25 0.40129 0.19741 0.30 0.38209 0.23582 0.35 0.36317 0.27366 0.40 0.34458 0.31084 0.45 0.32636 0.34729 0.50 0.30854 0.38292 0.55 0.29116 0.41768 0.60 0.27425 0.45149 0.65 0.25785 0.48431 0.70 0.24196 0.51607 0.75 0.22663 0.54675 0.80 0.21186 0.57629 0.85 0.19766 0.60467 0.90 0.18406 0.63188 0.95 0.17106 0.65789 1.00 0.15866 0.68269 |
Z(k) PROBRT PROBCENT 1.05 0.14686 0.70628 1.10 0.13567 0.72867 1.15 0.12507 0.74986 1.20 0.11507 0.76986 1.25 0.10565 0.78870 1.30 0.09680 0.80640 1.35 0.088508 0.82298 1.40 0.080757 0.83849 1.45 0.073529 0.85294 1.50 0.066807 0.86639 1.55 0.060571 0.87886 1.60 0.054799 0.89040 1.65 0.049471 0.90106 1.70 0.044565 0.91087 1.75 0.040059 0.91988 1.80 0.035930 0.92814 1.85 0.032157 0.93569 1.90 0.028717 0.94257 1.95 0.025588 0.94882 2.00 0.022750 0.95450 |
Z(k) PROBRT PROBCENT 2.05 0.020182 0.95964 2.10 0.017864 0.96427 2.15 0.015778 0.96844 2.20 0.013903 0.97219 2.25 0.012224 0.97555 2.30 0.010724 0.97855 2.35 0.009387 0.98123 2.40 0.008198 0.98360 2.45 0.007143 0.98571 2.50 0.006210 0.98758 2.55 0.005386 0.98923 2.60 0.004661 0.99068 2.65 0.004025 0.99195 2.70 .0034670 0.99307 2.75 .0029798 0.99404 2.80 .0025551 0.99489 2.85 .0021860 0.99563 2.90 .0018658 0.99627 2.95 .0015889 0.99682 3.00 .0013499 0.99730 |
From 2.35 0.009387
0.98123, z=2.35
n = 56
e = 36
p = 36/56 ≈ 0.64286
sdp = sqrt(p*(1-p)/n) = sqrt((36/56)*(20/56)/56) ≈ 0.064030
lowCI = p − z*sdp = 0.64286 − 2.35*0.064030 ≈ 0.49239
highCI = p + z*sdp = 0.64286 + 2.35*0.064030 ≈ 0.79333
Report the interval as
[.492, .793 ].
Interpretation
Our population is the
population of year 2005 US resident live born infants and our population mean
is the mean gestational age (weeks). Our event is that the live born infant was
born with between 37 and 40 weeks of gestation.
Our Family of Samples (FoS) consists of every possible random sample of 56
year 2005 US resident live born infants. From each individual sampled live born
infant, gestational age in weeks is obtained.
From each member sample
of the FoS, we compute the sample
proportion p of infants in the sample with between 37 and 40 weeks of gestation
at birth and sdp, where sdp=sqrt(p*(1-p)/56), and then compute the interval
[p – 2.35*sdp, p + 2.35*sdp].
Computing this interval
for each member sample of the FoS, we obtain a Family of Intervals (FoI), approximately 98% of which cover the true
population proportion of year 2005 US resident live born infants with between
37 and 40 weeks of gestation.
If our interval, [.492,
.793] is among the approximate 98% super-majority of intervals that cover the
population mean, then between 49.2% and 79.3% of year 2005 US resident live
born infants have gestation ages between 37 and 40 weeks.
Case List and Expected Progress
Descriptive Statistics – Complete
Summary/Descriptive Intervals – In Progress,
Nearly Complete
Confidence Interval – Population Mean – In
Process
Confidence Interval – Population Proportion –
Begin Work
Remaining Case Work
Hypothesis Test – Population Median
Hypothesis Test – Population Category /
Goodness of Fit